Skew-symmetric matrix Study

n mathematics, and in particular linear algebra, a skew-symmetric (or antisymmetric or antimetric[1]) matrix is a square matrix A whose transpose is also its negative; that is, it satisfies the equation A = −AT. If the entry in the i th row and j th column is aij, i.e. A = (aij) then the symmetric condition becomes aij = −aji. For example, the following matrix is skew-symmetric:

\begin{bmatrix}
0 & 2 & -1 \\
-2 & 0 & -4 \\
1 & 4 & 0\end{bmatrix}.



Properties

We assume that the the underlying field is not of characteristic 2: that is, that 1 + 1 ≠ 0 where 1 denotes the multiplicative identity and 0 the additive identity of the given field. Otherwise, a skew-symmetric matrix is just the same thing as a symmetric matrix.

Sums and scalar multiples of skew-symmetric matrices are again skew-symmetric. Hence, the skew-symmetric matrices form a vector space. Its dimension is n(n−1)/2.

Let Matn denote the space of n × n matrices. A skew-symmetric matrix is determined by n(n − 1)/2 scalars (the number of entries above the main diagonal); a symmetric matrixis determined by n(n + 1)/2 scalars (the number of entries on or above the main diagonal). If Skewn denotes the space of n × n skew-symmetric matrices and Symn denotes the space of n × n symmetric matrices and then since Matn = Skewn + Symn and Skewn ∩ Symn = {0}, i.e.

 \mbox{Mat}_n = \mbox{Skew}_n \oplus \mbox{Sym}_n ,

where ⊕ denotes the direct sum. Let A ∈ Matn then

 A = \frac{1}{2}(A - A^{\top}) + \frac{1}{2}(A + A^{\top}) .

Notice that ½(A − AT) ∈ Skewn and ½(A + AT) ∈ Symn. This is true for every square matrix A with entries from any field whose characteristic is different from 2.

As to equivalent conditions, notice that the relation of skew-symmetricity, A=-AT, holds for a matrix A if and only if one has xTAy =-yTAx for all vectors x and y. This is also equivalent to xTAx=0 for all x (one implication being obvious, the other a plain consequence of (x+y)TA(x+y)=0 for all x and y).

All main diagonal entries of a skew-symmetric matrix must be zero, so the trace is zero. If A = (aij) is skew-symmetric, aij = −aij; hence aii = 0.

[edit]Determinant

Let A be a n×n skew-symmetric matrix. The determinant of A satisfies

det(A) = det(AT) = det(−A) = (−1)ndet(A). Hence det(A) = 0 when n is odd.

In particular, if n is odd, and since the underlying field is not of characteristic 2, the determinant vanishes. This result is called Jacobi's theorem, after Carl Gustav Jacobi(Eves, 1980).

The even-dimensional case is more interesting. It turns out that the determinant of A for n even can be written as the square of a polynomial in the entries of A (Theorem byThomas Muir):

det(A) = Pf(A)2.

This polynomial is called the Pfaffian of A and is denoted Pf(A). Thus the determinant of a real skew-symmetric matrix is always non-negative.

The number of terms s(n) in the expansion of a skew-symmetric matrix of order n has been considered already by Cayley, Sylvester, and Pfaff. Due to cancellations, this number is quite small as compared the number of terms of a generic matrix of order n, which is n!. The sequence s(n) (sequence A002370 in OEIS) is

1, 0, 2, 0, 6, 0, 120, 0, 5250, 0, 395010, 0, …

and it is encoded in the exponential generating function

\sum_{n=0}^\infty \frac{s(n)}{n!}x^n=(1-x^2)^{-\frac{1}{4}}\exp\left(\frac{x^2}{4}\right).

The latter yields to the asymptotics (for n even)

s(n)=\pi^ {-\frac{1}{2} } 2^ {\frac{3}{4}} \Gamma\left (3/4 \right) (n/e)^ {n-\frac{1}{4} } \left (1+O\big(\frac{1}{n}\big)\right).

The number of positive and negative terms are approximatively a half of the total, although their difference takes larger and larger positive and negative values as n increases (sequence A167029 in OEIS).

[edit]Spectral theory

The eigenvalues of a skew-symmetric matrix always come in pairs ±λ (except in the odd-dimensional case where there is an additional unpaired 0 eigenvalue). For a real skew-symmetric matrix the nonzero eigenvalues are all pure imaginary and thus are of the form iλ1, −iλ1, iλ2, −iλ2, … where each of the λk are real.

Real skew-symmetric matrices are normal matrices (they commute with their adjoints) and are thus subject to the spectral theorem, which states that any real skew-symmetric matrix can be diagonalized by a unitary matrix. Since the eigenvalues of a real skew-symmetric matrix are complex it is not possible to diagonalize one by a real matrix. However, it is possible to bring every skew-symmetric matrix to a block diagonal form by an orthogonal transformation. Specifically, every 2n × 2n real skew-symmetric matrix can be written in the form A = Q Σ QT where Q is orthogonal and

\Sigma = \begin{bmatrix}
\begin{matrix}0 & \lambda_1\\ -\lambda_1 & 0\end{matrix} &  0 & \cdots & 0 \\
0 & \begin{matrix}0 & \lambda_2\\ -\lambda_2 & 0\end{matrix} &  & 0 \\
\vdots &  & \ddots & \vdots \\
0 & 0 & \cdots & \begin{matrix}0 & \lambda_r\\ -\lambda_r & 0\end{matrix} \\
& & & & \begin{matrix}0 \\ & \ddots \\ & & 0 \end{matrix}
\end{bmatrix}

for real λk. The nonzero eigenvalues of this matrix are ±iλk. In the odd-dimensional case Σ always has at least one row and column of zeros.

Leave Comments


profilehttp://nimablog.com 

Recent Post

Recent Trackback


T-NAVI